2x(x-1)=3x^2+1

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Solution for 2x(x-1)=3x^2+1 equation: 



2x(x-1)=3x^2+1

We move all terms to the left:

2x(x-1)-(3x^2+1)=0

We multiply parentheses

2x^2-2x-(3x^2+1)=0

We get rid of parentheses

2x^2-3x^2-2x-1=0

We add all the numbers together, and all the variables

-1x^2-2x-1=0

a = -1; b = -2; c = -1;
Δ = b2-4ac
Δ = -22-4·(-1)·(-1)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{2}{-2}=-1$

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